The number of ways of arranging all the letters of the word "$COMBINATIONS$" around a circle so that no two vowels come together is

  • A
    $\frac{7!6!}{(2!)^4}$
  • B
    $\frac{7!6!}{(2!)^3}$
  • C
    $\frac{{ }^{8}P_{5} \times 6!}{(2!)^3}$
  • D
    $\frac{7! \times { }^{8}P_{5}}{(2!)^3}$

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